A good answer might be:

No. A jump instruction causes the processor to fetch whatever bit pattern is stored in memory at the new address. This might not be part of the program.

Practice

Here is another schematic program. The instructions are just sketched in as place holders. Don't pay much attention to them, but look at the jump instruction and its target.

AddressInstruction
(details omitted)		PC just after this
instruction has executed
(at the bottom of the cycle)
.......................... 00450000
00450000 load 00450004
00450004 load 00450008
00450008 add 0045000C
0045000C store 00450010
00450010 jump 0x00450000 004500__
00450014 no-op 004500__

The target of the jump instruction is the address 0x00450000.


QUESTION 4:

Fill in the blanks.