QUESTION 12:
Is there a floating point absolute value instruction?
Say that x is very close to n0.5.
What do you think will be the value of n/(x*x)?
It should be very close to 1.0
But, due to the lack of precision with single precision, the best we can
hope for is to calculate an x such that:
0.999999 < n/x*x < 1.00001
The left and the right bound in the above have 6 decimal digits of precision. If 1.00000 is subtracted from this value the result is:
-0.000001 < n/x*x - 1 < 0.00001
To be safe, terminate the loop when:
| n/x*x - 1 | < 0.00001
... where |x| means the absolute value of x.
Is there a floating point absolute value instruction?