What is sixteen times 8B3 ?
8B30
Adding a 0 to the end of an integer written in base sixteen multiplies the integer by sixteen. To multiply an integer by sixteenN, add N zeros on the right:
8B3 × 103 = 8B3000 (Here 10 means sixteen.)
Erasing a digit on the right divides an integer by sixteen (integer division). So 8B3 div sixteen = 8B (with a remainder of 3).